Hi! A car starts at rest a certain distance (150m) away from edge of a cliff (64m high.) If car can accelerate at a certain rate (3.10m/s/s), how far from bottom of cliff will the car land?

I have know idea where to start on this question. Any help would be great.
Thanks

Hello triggerhorse

First you calculate how fast the car drives at the moment it leaves the cliff.
You have than a horizontal force (speed), a vertical force (gravity), and a vertical distance (64 meter). Calculate how long it takes to fall 64 meter.
Than calculate how far the car will travel forwards during that time.
Consider the air resistance nill.
Is that enough for you to calculate the distance?

Note : there is a Home --> Education --> Homework Help --> Math Board for this type of questions!

Hello triggerhorse

First you calculate how fast the car drives at the moment it leaves the cliff.
You have now a horizontal force (speed), a vertical force (gravity), and a vertical distance (64 meter). Calculate how long it takes to fall 64 meter.
Than calculate how far the car will travel forwards during that time.
Consider the air resistance nill.
Is that enough for you to calculate the distance?

Note : there is a Home --> Education --> Homework Help --> Math Board for this type of questions!

Hi! Thanks for the reply. How would I calculate "how fast the car drives at the moment it leaves the cliff?" If I know this, then I think I can work out the question from there.

The distance to the edge of the cliff is 150m. The car is traveling horizontally so there is no vertical component. It accelerates (initial velocity = 0)

You should know the formula,

X = V_ot + \frac{1}{2}At^2

where t is time

That's all you need to know.

Thank you

Hello triggerhorse

With all this help and assuming this allowed you to solve the question, please let us have your calculation how far away the car will land from the bottom of cliff.

final step for me was

d=vit+0.5a(tsquared)
d=30.4(3.6)+0
d=109.4m
Not sure if it is correct. Sounds logical.