View Full Version : Error calculation
kesavan
Mar 2, 2009, 11:32 AM
I measure 20 oscillations time is 48 seconds. If the least count of that clock is 0.1 second.
What is the error for one(single) oscillation time?
Perito
Mar 4, 2009, 05:30 PM
48sec/20 = 2.4 sec/oscillation. The least count of the clock is 0.1 second. Therefore, I think the error in the period is 48±0.1/20 = 2.4 ± 0.005 sec/oscillation.
If I did this wrong, I would appreciate someone telling me. It's been a while since I've done this.
kesavan
Mar 6, 2009, 10:28 AM
one oscillation time is 2.4 s
so error per single oscillation is ±0.1/48*2.4=±0.0005
acmmanoj
Jun 29, 2010, 11:06 PM
This is so wrong still the error is 0.1s. Division does not produce better accurate clock ( if you r correct)