If the probability of Team A winning against Team B is 91%. And the probability of Team C winning against Team D is 95%. What is the probability of Teams A and C both winning?
(Calculation and answer please)

If you flip a coin twice, where the probability of heads "winning" over tails is 50%, what's the probability of heads "winning" both times?

How can you apply the answer to this simple case to your problem?

If you flip a coin twice, where the probability of heads "winning" over tails is 50%, what's the probability of heads "winning" both times?

How can you apply the answer to this simple case to your problem?

I am not. You mentioned coin flipping; not me.

Here's the method for doingthis. If the probability of one event occurring is p, and the probability of a different event occurring is q, then the probability of both events occurring is p*q. A caveat: for this to work the two events must be independent - that is, the outcome of one event does not influence the outcome of the other. For your problem I think it's safe to assume that the outcomes of the two games are independent.