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mustang63
Feb 11, 2009, 08:55 PM
find three consecutive integers such that the sum of the second and third exceeds half of the first by 33

Capuchin
Feb 12, 2009, 12:55 AM
(n+1)+(n+2) = (n/2) + 33

Solve for n. (n is the first of the 3 integers)