Solve each trig. Equation for x in interval 0 < x < 360

a) 8sin^2x - 8sinx + 1 = 0

b) sin(x + 360/4) = (squared 2) cos x

a) 8sin^{2}(x) - 8sinx + 1 = 0

Treat this as a quadratic. Let u=sin(x)

Then, we get 8u^{2}-8u+1=0

Solve.