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hollyk
Nov 30, 2008, 09:39 PM
I can't seem to figure this out...

tanx/cscx=secx-cosx

ebaines
Dec 1, 2008, 08:04 AM
It almost always works best if you substitute sines and cosines for the tangent, cosecant etc.

The left hand side is:

tanx/cscx = (sinx/cosx)*(sinx/1) = sin^2x/cosx

The right hand side is:

secx - cosx = 1/cosx - cosx = 1/cosx - cos^2x/cosx = (1 - cos^2x)/cosx

Can you take it from here?

hollyk
Dec 1, 2008, 02:46 PM
Yes thanks