a 1.2 x 10^4 kg truck is travelling south at 22m/s

a) what net force is required to bring the truck to a stop in 330m ?

b) what is the cause of this net force?



well for a) I've decided to plot in to an equation

vf^2= vi^2 + 2ad

0 = (484) + 2a(330)

I'm sorry but I forgot how to solve the equation above.

do you do 484/330 and /2 again ?
I'm very confused on how to solve for a.
please help

You have:

0 = 484 + 2a(30)

The goal here is to get the "a" all by itself. First, subtract 484 from both sides:

-484 = 2a(30)

Now divide both sides by 2*30m:
-484/60 = a

Simplify:

a = - 8.0667 m/s^2.

Finally, double check the answer by substituting it back into the original equation to see if it works:

0 = 484 - 2(8.06667)(30) ?

0 = 484 - 484

Yep, it works.