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View Full Version : Point-Slope Form of a Linear Equation?


Simone21295
Nov 20, 2008, 02:42 PM
how do you the find the POINT-SLOPE OF A LINEAR EQUATION

rebel-2
Nov 20, 2008, 03:19 PM
hey there, I'm not sure what "point slope" is but I'm guessing that it is the equivalent to what we call gradient

liner equations look like this correct? y=mx+c
the "m" in this situation is the gradient of the graph. Also known as the slope of the graph.


OK to find the "equation" of a line this is what you do.
You first see where the line crosses the y axis (this is the y intercept, represented by the "c" in the equation.) then you find the gradient.

In order to do this, you see how much the line has increased by divided over how much it has traveled by.

People also say "Rise/run".

Just pick two points on the line and divide the change in y over change in x.


- I hope I haven't confused you.

EDIT:
here I found this on the net. Basically you divide Dy/Dx to get the gradient.
http://www.teacherschoice.com.au/Maths_Library/Functions/y_=_mx7.gif


Here's a site that explains this properly. http://www.mathsteacher.com.au/year10/ch03_linear_graphs/02_gradient/line.htm


-cheers.