Hello

I have the following sequence

1 + 1.02p2 + 1.02p3+... + 1.02p19

p: to the power

Can anyone please help me derive a formula for it?

Many thanks in advance
Kind regards,
Nitisha

1 + 1.02^2 + 1.02^3 + \dots + 1.02^{19}

Wouldn't you just solve that? (Oh, and is there a term missing; should there be a + 1.02 from 1.02^1 in there?). According to my calculator,

1 + \sum_{n=2}^{19}\left( 1.02^n \right) \approx 23.2774

If that was an accidentally missed term, then:

\sum_{n=0}^{19}\left( 1.02^n \right) \approx 24.2974