Considering acceleration is 10 m/s^2.
So what is acceleration of 46 kg pail of cement that is pulled upward with force of 296 N?What formulas what I use to solve it?

first, know that F = ma

find the net force (vertical)

downward force is (46)(10) = 460 N

upward force is 296 N

find net force

460 - 296 = 164 downward

F = ma

164 = (46)(a)

solve for a.

Yea I still can't get the right answer...