I have got to make c the subject of the formula. Ive been able to do the rest but this one puzzled me.

a+bc=5-3c

Thanks for anyone who can help me

First thing is to rearrange so that all the terms with c in them are on one side, and all the terms without c are on the other:

bc+3c = 5-a

Now pull out the c as a common term on the right hand side:

c(b+3) = 5-a

Now divide though by (b+3):

c = (5-a)/(b+3)