View Full Version : Where to start?
notamathwiz
Aug 13, 2008, 06:41 AM
I am having a problem starting this question. I have tried 3 ways and every time I am getting the wrong answer.
The problem is:
Solve for X:
10^2x-1=10^10
For anyone who can help me start this I would really appreciate it. You are the best!
galactus
Aug 13, 2008, 07:20 AM
Please use proper grouping symbols.
Is it 10^{2x-1}=10^{10}
or
10^{2x}-1=10^{10}
I will assume the former:
(2x-1)log(10)=10log(10)
What is log(10)? That makes it easy.
notamathwiz
Aug 13, 2008, 07:29 AM
Please use proper grouping symbols.
Is it 10^{2x-1}=10^{10}
or
10^{2x}-1=10^{10}
I will assume the former:
(2x-1)log(10)=10log(10)
What is log(10)?. That makes it easy.
It is the former problem. Log (10) is 1. Thank you!
notamathwiz
Aug 13, 2008, 07:53 AM
Please use proper grouping symbols.
Is it 10^{2x-1}=10^{10}
or
10^{2x}-1=10^{10}
I will assume the former:
(2x-1)log(10)=10log(10)
What is log(10)?. That makes it easy.
I am assuming I would take it from there in by doing:
(2x-1) log(10)=10log(10)
2x-1 = 10
2x = 11
11/2
and that's what x = or 5 1/2
Rehaan_genius
Aug 13, 2008, 08:00 AM
Hey dude! You got it right. 5 1/2 is 11/2! I think you are asking this,huh?