I am having a problem starting this question. I have tried 3 ways and every time I am getting the wrong answer.

The problem is:

Solve for X:

10^2x-1=10^10

For anyone who can help me start this I would really appreciate it. You are the best!

Please use proper grouping symbols.

Is it 10^{2x-1}=10^{10}

or

10^{2x}-1=10^{10}

I will assume the former:

(2x-1)log(10)=10log(10)

What is log(10)? That makes it easy.

Please use proper grouping symbols.

Is it 10^{2x-1}=10^{10}

or

10^{2x}-1=10^{10}

I will assume the former:

(2x-1)log(10)=10log(10)

What is log(10)?. That makes it easy.


It is the former problem. Log (10) is 1. Thank you!

Please use proper grouping symbols.

Is it 10^{2x-1}=10^{10}

or

10^{2x}-1=10^{10}

I will assume the former:

(2x-1)log(10)=10log(10)

What is log(10)?. That makes it easy.

I am assuming I would take it from there in by doing:

(2x-1) log(10)=10log(10)

2x-1 = 10

2x = 11

11/2

and that's what x = or 5 1/2

Hey dude! You got it right. 5 1/2 is 11/2! I think you are asking this,huh?