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notamathwiz
Jul 7, 2008, 04:37 PM
Just making sure I did this right...

If f(x)=x squared + 1
Find f (t+1)

I got F (t+1) squared



Just to let everyone know, you all are awesome for helping on these questions!! :)

morgaine300
Jul 8, 2008, 12:29 AM
You insert the (t + 1) in for the x correctly, but didn't carry the "+ 1" on the end with it. That isn't the same "+ 1" as the one for the x. It's completely separate.

Put parenthesis around the x in the function. Then replace that x with the (t + 1), but keep everything else. See what I mean?

(Is that an acceptable answer, or are you also supposed to foil, combine like terms & all that?)

Unknown008
Jul 8, 2008, 03:43 AM
Well, I'll make it clearer. I'll follow the same procedures as morgaine300, if you didn't understand her:

So, you have: f(x) = x^2 + 1

replace 'x' by (t + 1)

f(t+1) = (t+1)^2 + 1

Then you simplify.