View Full Version : Substitution for Algebra
jananewbould
Jun 26, 2008, 11:40 AM
So I have this problem:
x + 2y + z = 0
-3x + 3y + 2z= -7
4x - 2y - 3z= 2
Does anyone know the steps I should use to solve this using substitution?
HELP!
Thanks
Jana
ebaines
Jun 26, 2008, 11:46 AM
Usually the best place to start is to look at the equations and decide which would be easiest to rearrange to get either the x, y, or z by itself on one side. In this case the first equation looks simplest, since neither the x nor z term have coefficient and the right hand side is zero. So pick either the x or z and get it all alone on one side of the equation. For example, you can rearrange it to get:
x = 0-2y-z = -2y +z.
Now sub for that in the other two equations:
-3(-2y-z) + 3y +2z = -7
4(-2y-z) -2y - 3z = 2
You now have 2 equations in 2 unknowns. Can you take it from here?
nuclear_sugar
Jun 26, 2008, 11:53 AM
I remember when I learned it... but I can't remember much about the solution, except that you have to "add the equations" together, like putting them as you had written them above, then adding each variable together... but I think you somehow have to do it as many times as you have variables, and for that, I CANNOT remember how! I even made straight A's in it, but it's been a decade since I've used it. Sorry! Good luck!
Unknown008
Jun 27, 2008, 03:29 AM
That method I think is called elimination method, whereby you get rid of some variables, leaving those you can deal with more easily
Mckenzie1046
Jan 5, 2009, 05:00 PM
The question was concerning how to use elimination in solving the equation. The answer given was how to solve the equation by substitution and therefore not helpful.