A banquet hall offers a chicken dinner for $16 and a beef dinner for $18. 300 guests have orderd their meals in advance, and the total cost for the wedding is $5256. How many of each type of dinner was orederd?

You have a small system of equations to solve.

Let x = the number of chicken dinners and y=the number of beef dinners.

So, x+y=300

But the chicken costs 16 and the beef 18. This totals 5256.

16x+18y=5256

Solve the system and you're in business.