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View Full Version : Finding x & why intercepts


maricelalvarez
Jun 19, 2008, 02:57 PM
I am having trouble trying to solve this problem if anyone can help I would greatly appreciate it

for the quadric function f(x)=5.74x^2-3.135x-5.79, find the maximum or the minimum value,the x-intercepts, & the y-intercepts?

galactus
Jun 19, 2008, 06:09 PM
y=5.74x^{2}-3.135x-5.79

The vertex can be found by the simple formula, x=\frac{-b}{2a}

Then plug that back into your function to find the y-coordinate.

To find the y intercept, set x=0.

To find the x-intercept, set y=0 and solve by factoring, quadratic formula, completing the square, whatever.