Is this transpostion/rearrangement to make h subject correct?

question: I = 1
---- bh^3
12

My answer: h = (I12/b) ^ 1/3


Please help me. Thanks

Looks right to me

thank you. How about this.

(R+wL)(R-wL)

= R^2 -wL

That is the difference of two squares.

Should be R^{2}-(wL)^{2}