View Full Version : Differentiation, surface area
Shidah
Jun 16, 2008, 12:28 AM
how to differentiate A=4x^2 + 216/x? I got stuck at 216/x?
Capuchin
Jun 16, 2008, 12:40 AM
\frac{1}{x} = x^{-1}
therefore:
4x^2 + \frac{216}{x} = 4x^2 + 216x^{-1}
Go from there
Shidah
Jun 16, 2008, 01:06 AM
\frac{1}{x} = x^{-1}
therefore:
4x^2 + \frac{216}{x} = 4x^2 + 216x^{-1}
Go from there
so, it will be 8x - 216x^-2?
the full question is given a rectangular ( 2x by x by x)
the volume is 72cm3.
the total surface area is A=4x^2 + 216/x.
find the minimum value of the total surface area?
i don't know how to start.
Capuchin
Jun 16, 2008, 03:30 AM
so, it will be 8x - 216x^-2?
the full question is given a rectangular ( 2x by x by x)
the volume is 72cm3.
the total surface area is A=4x^2 + 216/x.
find the minimum value of the total surface area?
i dont know how to start.
That's right, so now you know that when dA/dx is 0, A is either at a maximum, minimum, or a reflex point. To find out which, you can look at d^2A/dx^2 , which should be positive for a minimum.
Unknown008
Jun 17, 2008, 05:16 AM
And solve for dA/dx = 0