An object moving with uniform acceleration has a velocity of 14.0 cm/s in the positive x direction when its x coordinate is 3.00 cm. If its x coordinate 1.80 s later is -5.00 cm, what is its acceleration?

Use the formula:


x_f = x_i + v_i t + \frac 1 2 a t^2


Here x_i is +3 cm, x_f is -5 cm, v_i is +14 cm/s, and t is 1.8s. Solve for a.