Elimination with Multiplicationhelp pleaseeeee! :confused:


1. -3x+ 2y = 10
-2x - y = -1



2. 2x + 5y = 13
4x - 3y = -13

3. 5x +3y =4
-4x+ 5y = -18

4. 1/3x - y = -1
1/5x - 2/5y = -1

5. 3x-5y =8
4x-7y = 10

6. x- 0.5y = 1
0.4x + y = -2

7. x+ 8y = 3
4x - 2y +7

8. 4x - y = 4
x+ 2y = 3

9. 3y - 8x = 9
y - x =2

10. X + 4y = 30
2x - y = -6

11. 3x - 2y = 0
4x + 4y = 5

12. 9x - 3y = -9
-8x + 2y = 4

13. 2x - 7y= 9
-3x + 4y = 6

14. 2x- 6y = -16
5x+ 7y = -18

15. 6x - 3y = -9
-8x + 2y = 4

Did you expect someone to just do all these for you?

Here at AMHD we have homework guidelines:

https://www.askmehelpdesk.com/arts-literature/announcement-font-color-ff0000-u-b-read-first-expectations-homework-help-board-b-u-font.html

I will do the first one using elimination. Then you try some and see how it goes. Okey-doke?

#1:

-3x+2y=10

-2x-y=1

The thing to do is look at it and see what you can multiply one line by so that when you add them a variable is elimination. That's why it's called the elimination method.

Multiply the bottom row by 2. That way you'll have -2y in the second row and 2y in the first. So, when you add them you get 0.

-3x+2y=10

-4x-2y=-2

Add them and get:

-7x=8

\fbox{x=\frac{-8}{7}}

Now, you can sub that in to get your y.

-4(\frac{-8}{7})-2y=-2

\frac{32}{7}-2y=-2

-2y=\frac{-46}{7}

\fbox{y=\frac{23}{7}}