1.If
f(x)=− 25/ (2x+3)
find

lim ( f(1+h)−f(1)) /h
h→ 0


2.lim (2t^2−3t−2)/(t^2+t-6)
t→ 2



3.lim (x^2+4x-5)/(x^2+x-2)
x→ 1



4.lim x^2 / |x|
x→ 0




5.lim 1/|x|
x→ 0

1.If
f(x)=− 25/ (2x+3)
find

lim ( f(1+h)−f(1)) /h
h→ 0

Plug in 1+h for x in your expression and reduce.





2.lim (2t^2−3t−2)/(t^2+t-6)
t→ 2

Long divide first. This is an indeterminate form.




3.lim (x^2+4x-5)/(x^2+x-2)
x→ 1


Same as #2






.lim x^2 / |x|
x→ 0

This is \frac{x^{2}}{x}=x or \frac{x^{2}}{-x}=-x





5.lim 1/|x|
x→ 0

Think of it as \frac{1}{\sqrt{x^{2}}}

Look at the graph.