MR Dale
May 7, 2008, 05:21 PM
What Is One Of The Extremes In Proportion 2:16::1:8?
MR Dale
May 7, 2008, 05:23 PM
solve for x in the following 3:80::x:150
galactus
May 8, 2008, 05:08 AM
Proportions are just like reducing fractions. For instance, suppose you had \frac{1}{2}=\frac{x}{6}
What would x be? 3, of course. So, for your problem do the same.
\frac{3}{80}=\frac{x}{150}. Solve for x.