:confused: the worked example does not help me at all as I can not make sense out of it. This is the example 9 "x" squared - 6 "x" plus one
=(3"x")squared - 2 multiplied by 3"x" multiplied by 1 + 1squared
=(3"x"-1)squared

when expanded how wold the get the origanal equation.

all my answers were wrong when I went to check my work

IF ANY ONE READING THIS IS INVOLVED IN STANDARD LEVEL MATHMATICS YEAR 11 IB THE QUESTIONS ARE TOP OF PAGE 250.

The book (if it is the same as mine) will be titled mathematics for the international student mathematical studies SL
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The example is correct. Starting with:


(3x-1)^2


It multiplies out as follows:

(3x-1)^2 = (3x-1) \cdot (3x-1) = 3x\cdot 3x + 3x\cdot (-1) + (-1)\cdot 3x + (-1) \cdot (- 1)\\
= 9x^2 - 6x +1