ISneezeFunny
Apr 30, 2008, 09:59 AM
Do what you can first. Then we'll help you along the way.
galactus
Apr 30, 2008, 11:26 AM
Suppose you used the logs as a power of 10. Like so:
10^{log(2x+1)}=10^{log(4x-5)}
Now, what do you end up with? Something much easier to solve. Don't get befuddled when you see the logs. It's much easier to solve than you think.