Q In a poker hand consisting of 5 cards, find the probability of holding
(a) 3 acres;
(b) 4 hearts and 1 club.

part a: \frac{C(4,3)C(48,2)}{C(52,5)}

part b. \frac{C(13,4)C(13,1)}{C(52,5)}

The poster isn't going to "get a clue" when all you did was dump equations and not explain how or why they work. Makes it a little difficult to apply it to the next problem.

I reckon you're absolutely correct, morgaine.

We are choosing 3 aces out of the 4, hence, C(4,3).

We have to choose 2 of any other card. There are 48 left, so C(48,2)

We are choosing 5 cards out of 52 altogether.

Therefore, we get the \frac{C(4,3)C(48,2)}{C(52,5)}.

I reckon you're absolutely correct, morgaine.



I have to say I'm totally impressed that you took that in a kind spirit and didn't just get angry. :)

(Or maybe it's just cause I've had people getting angry with me because I tell them to follow the site's rules and that I'm not here to do their homework for them... Sigh.)

I, too, have encountered my share of thin-skinned folks on these sites. When some advice is kindly given it is taken out of context and thought of as an insult when there was none intended.

Q In a poker hand consisting of 5 cards, find the probability of holding
(a) 3 acres;
(b) 4 hearts and 1 club.