jsham996
Jan 31, 2008, 02:43 AM
log (x + 17) - log (x - 1) + log (x) = 1
jiten55
Jan 31, 2008, 04:15 AM
Assuming base for log is 10:
log (x + 17) - log (x - 1) + log (x) = 1
[Log A + Log B - Log C = Log [(AB)/C] and 1 = Log 10 , assuming base is 10]
Log [(x +17)x/(x -1) ] = Log 10
(x +17)x/(x -1) = 10
x(x +17) = 10(x -1)
Solve this quadratic equation.