Log3(x+2)+ Log3(x-1)-2

Do you mean:


log_3 {(x+2)}\ +\ log_3{(x-1)}\ -\ 2?


First, try to get everything written in the same log base. Note that:

2 = log_3 9

and combine that with the property that log(abc) = log(a) + log(b) + log(c). So you have:


log_3 {(x+2)}\ +\ log_3{(x-1)}\ -\ 2\ =\ log_3 {(x+2)} +log_3 {(x-1)} +log_3 9 = log_3 {[9(x+2)(x-1)]}

I can help further. I saw it now and so I react now only, and so I ask you to inform if you are satiated or not, and if you need help write further. Thanks!