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jenniferbehr
Dec 12, 2007, 06:25 PM
how do I Solve:

Let the function of f be defined by f(x)=x(x) + 27. If f (3m)=3f (m) what are the possible values of m

galactus
Dec 12, 2007, 07:32 PM
Insert your 3m where needed and solve the resulting equation.

By x(x), I suppose you mean x^2?

Solve:

(3m)^{2}+27=3(m^{2}+27)

Solve for m.