answersplease
Dec 3, 2007, 02:15 PM
The mean of three numbers is 10,and their median is 10.3. If the difference between the largest and the smallest of the three numbers is 2, what are the three numbers?:p
N0help4u
Dec 3, 2007, 02:54 PM
don't know but
I like the nines
9x1=9
9x10=90 9+0=9
9x2=18 1+8=9
9x9=81 8+1=9
9x3=27 2+7=9
9x8=72 7+2=9
9x4=36 3+6=9
9x7=63 6+3=9
9x5=45 4+5=9
9x6=54 5+4=9
You can do the nines like this up to as high as you want to.
galactus
Dec 3, 2007, 04:01 PM
The mean of three numbers is 10: \frac{a+b+c}{3}=10
Their median is 10.3: a, 10.3, c
The difference between the largest and smallest is 2: c-a=2
c=2+a
b=10.3
\frac{a+10.3+(2+a)}{3}=10
Solving, we get a=8.85, b=10.3, c=10.85