View Full Version : Another Probability
Ail Bane
Dec 2, 2007, 01:25 AM
I was wondering if I got this question right.
A food distributor carries 64 varieties of salad dressing. Appleton Markets stocks 48 of these flavors. Beacon Stores carries 32 of them. The probability that a flavor will be carried by Appleton or Beacon is 15/16. Find the probability a flavor is carried by both Appleton and Beacon.
I thought the answer would be 3/8, am I wrong?
terryg752
Dec 2, 2007, 03:23 AM
VERY INTERESTING!
Obviously, A carries 48, B carries 32
AND (! ) A and B togather carry = 15/16 times 64 = 60
Hence B carries (60 - 48) = 12 that are NOT carried by A
Hence B carries (32 -12) = 20 that are also carried by A
\
Carried by BOTH = 20
Hence probability = 20/64 = 5/16
Please confirm if correct or not.
terryg752
Dec 2, 2007, 03:39 AM
FORMAL METHOD;
Remember:
P (C1 U C2) = P(C1) + P(C2) - P(C1 intersection C2)
and P (C1) = 48/64, P(C2) = 32/64, P(C1 U C2) = 15/16
HENCE P(C1 intersection C2) = 5/16
Ail Bane
Dec 3, 2007, 02:57 AM
EDIT: I re-read the problem and the line:
AND (!!) A and B togather carry = 15/16 times 64 = 60
Could that mean the same as OR (3rd sentence)?
--------------------------------------------------------------------------------------------------
I was close to being right :cool: . 3/8 or 6/16 was really close to your 5/16. Thanks for both the formal and informal method of solving probabilities. I understand how you arrived at the answer.
PS: I understood the informal method better.
Thanks again.:D
terryg752
Dec 3, 2007, 03:53 AM
It means that stores A and B (either or both) carry...
For example: A carries X and Y
B carries Y and Z
A and B together carry X, Y and Z
Ail Bane
Dec 4, 2007, 12:08 AM
Thanks again for being helpful.:D :cool: