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jen phoenix
Nov 21, 2007, 06:35 AM
If a 4-bit has 16 combinations of zeros and ones, how many combinations of zeros and ones in a 64-bit?
From 00000000000000000000000000000000000000000000000000 00000000000000 to
11111111111111111111111111111111111111111111111111 11111111111111 combinations...
Please.. thanks..

Curlyben
Nov 21, 2007, 06:38 AM
64-bit - Wikipedia, the free encyclopedia (http://en.wikipedia.org/wiki/64_bit)

Stratmando
Nov 21, 2007, 06:47 AM
That would be Binary 64 1's.
Binary 16 is 1111. (1,2,4,8)Add 1+2+4+8+0) is 16 different numbers.
You would have to keep doubling until you get to 64, then double it.
Just as above the 4th place is 8, but actual number is 16.
There is probably a formula. This is a dummies version. If you come up with an answer, will compare to my results. Good luck
You would want to write down the numbers 1 through 64, then beside them write:
1,2,4,8,16,32,64,128,256,512,1024, etc. 64 times. Numbers will be getting big.