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talaskinboit
Nov 7, 2007, 05:59 PM
what is the inverse cotangent of negative square root of three divided by three?

theta = cot(inverse) (negative Squareroot 3)/3
s_cianci
Nov 7, 2007, 06:15 PM
It's whatever angle, in radians, has a cotangent value of -sqrt(3)/3.