Can someone explain to me how to solve this equation:

(4/9)-1/2*



*Exponent


??

Can someone explain to me how to solve this equation:

(4/9)-1/2*



*Exponent


???
(4/9)-1/2*

= (9/4)1/2*

= Square root of (9/4)

= (Square root of 9)/(Square root of 4)

Can someone explain to me how to solve this equation:

(4/9)-1/2*



*Exponent


???

RULE:

a^(-b) = 1/a^(b)

We can use this rule to solve your negative fractional exponent question.

4/9 raised to the negative fraction -1/2 becomes 1/(4/9)^(1/2)... Notice that the fraction 1/2 became POSITIVE when moved to the right side of the equation. See it?

Our denominator--->this guy--> (4/9)^(1/2) can be written as a square root. We now have the square root of 4/9, which 2/3.

Our new fraction is 1/(2/3).

What is 1 divided by 2/3?

Final answer: 3/2.

(x^(1/2)-2x^(-1/2))/(x^(-1/2))

bryndle - please do not tag a new question onto an old thread. Instead you should start a new question. But to help out...

Remember that:


\frac {x^a} {x^b} = x^{(a-b)}


For example:


\frac {x^{1/2)}} {x^{-(1/2)}} = x^{(1/2 - (-1/2))} = x

can you take it from here?