View Full Version : Pythagorean triples?
FLchickie
Oct 15, 2007, 03:29 PM
Never used this site so bear with me :D
Ok a question from my schoolbook:
Which of the following sets are Pythagorean triples?
Im pretty sure I got the first three right but not sure how to do this one at all:
3^2, 4^2, and 5^2.
Does the fact that there is already a 2 there mean I should square it twice??
HELP!!
Thanks!
ebaines
Oct 15, 2007, 03:36 PM
Never used this site so bear with me :D
Ok a question from my schoolbook:
Which of the following sets are Pythagorean triples?
Im pretty sure I got the first three right but not sure how to do this one at all:
3^2, 4^2, and 5^2.
Does the fact that there is already a 2 there mean I should square it twice???
HELP!!!
Thanks!
A Pythagorean triple consists of 3 integers a, b, and c, where a^2 + b^2 = c^2. Hence 3, 4, and 5 are a Pythagorean triple, since 3^2 + 4^2 = 5^2. However, 3^2, 4^2 and 5^2 is NOT a Pythagorean triple, since 9^2 + 16^2 does not equal 25^2.
FLchickie
Oct 15, 2007, 05:35 PM
Sweet man, thanks. I was really messed up over this!
FLchickie
Oct 17, 2007, 12:35 PM
I thought I had the other two answers yest but now I rechecked and Im not sure.
The square root of 3, the square root of 4, and the square root of 5 are NOT Pyth. Triples correct? It equals out to 3+4=5 which is incorrect.
And for 1/3,1/4, and 1/5 I got 1/9+1/16=1/25 so that isn't one either?
ebaines
Oct 17, 2007, 12:42 PM
I thought I had the other two answers yest but now I rechecked and Im not sure.
The square root of 3, the square root of 4, and the square root of 5 are NOT Pyth. triples correct? It equals out to 3+4=5 which is incorrect.
And for 1/3,1/4, and 1/5 I got 1/9+1/16=1/25 so that isnt one either?
That's right - these are NOT Pythagorean triples.