Use the In ket to express each number as a power . Then use the rules of logarithms to find the answer

(45,332 * 10^5) (33,654 * 10^4)
----------------------------------------
93.153

OK I am checking in my book
looking at a sample of such problems.

first I want to ask that should I multiply the numbers first and have it look like this:

(453,320^5) (336,540^-4)
-------------------------------
93.153

so than solve the numbers which have the over sign with it
or what?

I know I have to use the In ket on the calculator to write each number as e raised to a power
all the parts are easy I know and I see that also

I just want to know that should it be like this or not?
(453,320^5) (336,540^-4)
-------------------------------
93.153

then

(1.914363479) (7.795666263)
-----------------------------------
93.153

if this is wrong do stop me and let me know where did I go wrong?

You have some things incorrect from the outset. Sorry.

You can rewrite the denominator as: 10^{8}\cdot{453320}\cdot{33654}

Taking the log gives: 8log(10)+log(453320)+log(33654)-log(93.153)

That is 10^{\text{(answer from above here})}

16.21424472