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Solving compound linear inequalities
kayla_coop
Sep 29, 2007, 11:47 AM
2p-2 is lssthan/equalto 4p-8is lessthan/equalto 3p-3
Could you help me:confused:
galactus
Sep 29, 2007, 01:25 PM
There are different approaches.
2p-2\leq{4p-8}\leq{3p-3}
Factor:
2(p-1)\leq{4(p-2)}\leq{3(p-1)}
Divide by p-1:
2\leq{4(\frac{p-2}{p-1})}\leq{3}
2\leq{4-\frac{4}{p-1}}\leq{3}
2\geq{\frac{4}{p-1}}\geq{1}
Now, can you finish.