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View Full Version : LIMITS at negative. Infinity!


nevermorex
Sep 18, 2007, 02:57 PM
Without graphing, how do you take the limit of the cubed root of x as x approaches negative infinity?

Help me, please.

galactus
Sep 18, 2007, 06:54 PM
x^{\frac{1}{3}} is a continuous function. Therefore, you can use

(-\infty)^{\frac{1}{3}}={-\infty}