Blondie2007
Sep 16, 2007, 11:31 AM
So, I have the equation y= -3(x-2)^2-13
I tried to find the x-intercepts so that I could graph the parabola, but I got this crazy answer:
-2 plus or minus the square root of 39 over negative 3
??
I tried to find the x-intercepts so that I could graph the parabola, but I got this crazy answer:
-2 plus or minus the square root of 39 over negative 3
??