:confused: :confused: Hi trying to figure out a problem: you have a deck of 52 cards with 4 aces, assume you give 13 cards to each of 4 players, what is the prob that each players gets one ace?

That all seems correct to me.

The first player gets 13 cards, one of which must be an Ace.

The probability of that player being dealt an Ace among the 13 cards is:

\frac{C(48,12)C(4,1)}{C(52,13)}

Can you continue for the next 3 players? Give it a go and write back with your thoughts.

There used to be a formula up there... where did it go?

I still see it?

The one from the OP? I don't see it anymore...

I never saw the OP one. There's not a link when I go to edit it.

Lol I guess they edited it... now my first response doesn't quite make sense... oh well.. lol.

Any thoughts, other than what happened to the post?

The probability of each player receiving one Ace is:

\frac{C(48,12)C(4,1)}{C(52,13)}\cdot\frac{C(36,12) C(3,1)}{C(39,13)}\cdot\frac{C(24,12)C(2,1)}{C(26,1 3)}

Since the first three players have received their cards, just deal the other 13 out to the last player.