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ashleyneedshelp
Aug 2, 2007, 09:53 PM
ln2x-ln(x-2)=ln3

please help:eek:

zippthorne
Aug 2, 2007, 10:33 PM
The following identity should help:

ln(a) - ln(b) = ln(a/b)

s_cianci
Aug 4, 2007, 09:01 AM
Also, keep in mind that logarithms are one-to-one,meaning that, if the logarithms are equal, the arguments are equal.