How many grams of O2 can be produced by decomposing 100.0g of BaO2 to BaO and O2?

I started by balancing 2BaO2 yields 2BaO + O2

100.0g of BO2 x 1 mol O2 x 32g mol O2 = 18.9g of O2 produced
---------- ----------
169.3g BaO2 1 mol O2


I feel like I didn't set this up right. I thought I had to use the 2:1 rati of 2 BaO and 1 O2

Am I somewhat on the right track?

With 2BaO2-->2BaO+O2 u have 2 oxygens on one side and 3 on the other... may I suggest 4BaO2-->4BaO+2O2