View Full Version : Second derivative
giant_bob
Jul 19, 2007, 12:54 AM
Hello,
I am wondering how to differentiate an equation when I have a power of x and a constant in the denominator, for example:
y=a/(e^(x+b)+c), where a,b,c are any number bar zero.
I could do it easily without that c there, but this has me stumpped.
galactus
Jul 19, 2007, 04:27 AM
Just use the quotient rule.
\frac{a}{e^{x+b}+c}
Quotient rule:
\frac{(e^{x+b}+c)(0)-(a)(e^{x+b})}{(e^{x+b}+c)^{2}}
Now, simplify.
Do it again for the second derivative.
giant_bob
Jul 19, 2007, 04:40 AM
I thank you for your help once again kind sir.
I am now testing your advice to see whether I can apply it to my problem, however, I have yet another question.
I was under the impression that the quotient rule can only be used when there are powers of x in both the numerator and denominator, was I misinformed?
Capuchin
Jul 19, 2007, 04:44 AM
There are powers of x. x^0.
giant_bob
Jul 19, 2007, 04:57 AM
Ah, but of course. Thank you Capuchin.
There is one thing I'd like to clarify though.
I wouldn't use the quotient rule for something like a/x, however, I must use it in my question which is basically a/(x+b).
Is it due to this b value that I now need to use the quotient rule?
galactus
Jul 19, 2007, 01:19 PM
No, the b is just a constant. You use the quotient rule when you have a quotient.
You could also use the product rule.
a(e^{x+b}+c)^{-1}
Product rule:
a(-1)(e^{x+b}+c)^{-2}(e^{x+b})-(e^{x+b}+c)^{-1}(0)
Simplify and you'll get the same result as with the quotient rule.