who knows how to solve this problem...


logx^64=6

Do you mean:


log _x 64 = 6


Or do you mean:


log (x^{64}) = 6


Please clarify.

I mean the first one, yeah not the second one... you know how to solve it.

OK. Use the definition of the logarithm: if
log _A B = C
then that means that A^C = B. So in this case,
log _x 64 = 6
means that:
x^6 = 64.
Solve for x. Hope this helps.