I need to integrate 1000(2t+1)^-2

I thought it would go [(1000(2t+1)^-1)/-1 ] * t

Let u=2t+1, \;\ du=2dt, \;\ \frac{du}{2}=dt

This gives:

500\int\frac{1}{u^{2}}du

sorry how do you apply dt=du/2 to get 500(integral)(1/u^2)du

Hello

You are trying to solve:



\int \frac 1 {(2t+1)^2} dt



correct?

So replacing 2t+1 by u, and dt by du/2 gives you the form that Gallactus suggests. Now you should be able to integrate that form, and then the last step is to substitute 2t+1 for u to get the final answer.