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View Full Version : Trig identities


jbenevidesfh6
May 20, 2007, 01:57 PM
How can I solve..
cotx + cosx sinx/ tanx +conx sinx/ cotx = csc2?

galactus
May 20, 2007, 02:02 PM
Please clarify. Without proper grouping symbols your problem statement is rather ambiguous.

Is this what you mean?:

\frac{cotx+cosxsinx}{tanx}+\frac{cosxsinx}{cotx}=c sc(2)

ebaines
May 21, 2007, 11:31 AM
Do you mean:


cot(x) + \frac {cos(x) sin(x)}{tan(x)}+ \frac{cos(x) sin(x)}{cot(x)} = csc(2)


If so, then try rewriting using sin() and cos() in place of the tan() and cot() functons, and much of it collapses to a simpler looking equation. You'll end up having to determine the arc tan of a number.