I have the following part to a problem that I am struggling with. (see diagram attachment)

The water tank has a nozzle with an unknown diameter at a depth of 6.75m. The level of the tank will stay the same depth by being toped up.

What I am struggling with is calculating what diameter the nozzle needs to be to exert a force of 4291.8N on the plate? Anyone point me in the right direction? :confused: :confused:

Thanks

Well we can use a formula for hydrostatic pressure:

P = \rho g h

Then we can use The formula for pressure:

P = \frac{F}{A}

The area is circular so

A = \pi r^2

Putting these together:

\frac{F}{\pi r^2}= \rho g h

r = \sqrt{\frac{F}{\pi \rho g h}}

d = 2 \sqrt{\frac{F}{\pi \rho g h}}

Does this help?

Keep in mind that this formula is quite approximate, so it might not give you as accurate a force as you are desiring here.

Thanks that makes sense,
I've been told that bernoulli's law can be used to solve the problem, do you think it would be any more accurate?

I think bernoulli's law would require you to know the other dimensions of the tank.