A scientist measures the standard enthalpy change for the following reaction to be -888.2 kJ :

2NH3(g) + 3 N2O(g)http://cxp.cengage.com/contentservice/assets/T=1425187801638/owms01h/mediaarchives/GenChem/Image/Arrow.gif4N2(g) + 3 H2O(g)

Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of N2O(g) is

Ca(OH)2(aq) + 2 HCl(aq)http://cxp.cengage.com/contentservice/assets/T=1425187801638/owms01h/mediaarchives/GenChem/Image/Arrow.gifCaCl2(s) + 2 H2O(l)

Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H2O(l) is

A scientist measures the standard enthalpy change for the following reaction to be -51.0 kJ:

Ca(OH)2(aq) + 2 HCl(aq)http://cxp.cengage.com/contentservice/assets/T=1425187801638/owms01h/mediaarchives/GenChem/Image/Arrow.gifCaCl2(s) + 2 H2O(l)

Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H2O(l) is

A scientist measures the standard enthalpy change for the following reaction to be 154.4 kJ :

CaCO3(s)http://cxp.cengage.com/contentservice/assets/T=1425187801638/owms01h/mediaarchives/GenChem/Image/Arrow.gifCaO(s) + CO2(g)

Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of CaO(s) is

A scientist measures the standard enthalpy change for the following reaction to be 154.4 kJ :
CaCO3(s)http://cxp.cengage.com/contentservice/assets/T=1425187801638/owms01h/mediaarchives/GenChem/Image/Arrow.gifCaO(s) + CO2(g)

Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of CaO(s) is

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file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gifH°rxn = (2 mol)file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gifH°f(CO2(g)) + (1 mol)file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gifH°H°f(N2(g))(N2(g)) - [(2 mol)file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gifH°f(CO(g)) + (2 mol)file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gifH°H°f(NO(g))](NO(g))] = -780.8 kJ

Solve forfile:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gifH°f(CO2(g)) in the above equation:
file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gifH°f(CO2(g)) = [file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gifH°rxn - (1 mol)file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gifH°H°f(N2(g))(N2(g)) + (2 mol)file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gifH°f(CO(g)) + (2 mol)file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gifH°H°f(NO(g))](NO(g))] / (2 mol)

= [(-780.8 kJ) - (1 mol)(0.0 kJ/mol) + (2 mol)(-110.5 kJ/mol) + (2 mol)(90.3 kJ/mol)]/(2 mol)
= -410.6 kJ/mol