Good Afternoon,


I'm debating with a question and I'm not quite sure that I answered it right.


The question:
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The velocity in the beginning of the circular area is 120km/h. The R, curvature radius is 100m and the arc degree is 5º, 2.5º before the highest point and 2.5º after the highest point.
The question is, the car starts jumping in the highest point of the curve? In the beginning? Ou somewhere in the middle?


My answer:


If the car starts jumping then the normal reaction is 0 so the resultant force when the car is in the air is equal to the gravitic force: m*g.
In order to remain close to the ground m*g projected in the centripetal direction must be greater tha the centripetal force: m*g>m*ac
So, in the beginning of te curve: m*g*cos(2.5º)<m*(v^2)/r so the car starts jumping right here.


Am I right?

Am I right?

Yes indeed!