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View Full Version : Proving a rather difficult trigonometric identity


Cmegehee91
Mar 3, 2013, 12:14 PM
Can anyone prove, and show step by step, that

1 + cosx + sinx = secx + tanx
1 + cosx - sinx

Because I am absolutely stumped.

ebaines
Mar 4, 2013, 09:25 AM
Same advice as with your other recent post - convert the secant and tangent functions to their sine and cosibne equivalents, and simplfy. The only trick you will have to use is to recognize that 1-sin^2x = cos^2x.