the sum of three numbers is 247 the sum of the first and second exceeds the third by 95 the third integer is 85 less than the first find the 3 integers

1st integer: x
2nd : y
3rd : z

Sum of three integers:
x + y + z = 247 (1)

Sum of first 2 exceeds the 3rd by 95. In another word, sum of first two is larger than the 3rd by 95:

(x+y) - z = 95 (2)

Third is less than first 85:

x = z + 85 (3)

Take (1) minus (2)
x + y + z = 247
-
x + y - z = 95
----------------------
2z = 247 - 95 =??

Then divided by 2 to get z

Since you get z, plug into (3) to get x.
When you get x and z, plug x and z either in (1) or (2) to get y.